2011-7 Factorial

Let f(n) be the largest integer k such that n! is divisible by \(n^k\). Prove that \[ \lim_{n\to \infty} \frac{(\log n)\cdot \max_{2\le i\le n} f(i)}{n \log\log n}=1.\]

GD Star Rating
loading...
2011-7 Factorial, 4.8 out of 5 based on 16 ratings

3 thoughts on “2011-7 Factorial

Comments are closed.