## Seminars and Colloquium

#### Sungmun Cho (Postech)Number Theory Seminar

A reformulation of the Siegel series

#### Dohoon Choi (Korea University)Number Theory Seminar

Application of Langlands program to the Linnik problem for automorphic representations

#### Ji-Eun ChoiPh.D. Defense

Traveling Waves and Turning Patterns in Predator-prey Equations

#### Yeansu Kim (Chonnam National University)Number Theory Seminar

Classification of discrete series representations of odd GSpin groups

#### Michael Dobbins (Binghamton University, Binghamton, NY, USA)Discrete Math

Grassmanians and Pseudosphere Arrangements

#### Jon-Lark Kim (Department of Mathematics, Sogang University)Colloquium

Applications of Error-Correcting Codes to Games and Cryptography

#### Junwoo KimPh.D. Defense

Three-dimensional Volume Reconstruction Using Two-dimensional Parallel Slices

## Conferences and Workshops

## Bookmarks

## Bulletin Boards

고페이 수학강사 모십니다. | 08. 11 | |

중3 수학 과외 선생님 모십니다. | 04. 06 | |

여학생 과외 원합니다. | 03. 07 | |

고교2학년생입니다. 수학선생님 원해요 | 11. 11 | |

대학원 입시 설명회 자료 좀 올려주시겠어요? | 06. 22 | |

모듈 형식과 타원 방정식에 대해서 질문합니다 | 11. 13 | |

모듈 형식과 타원 방정식에 대해서 질문합니다 | 11. 13 |

## Alumni News

## Problem of the week

On a math exam, there was a question that asked for the largest angle of the triangle with sidelengths \(21\), \(41\), and \(50\). A student obtained the correct answer as follows:
Let \(x\) be the largest angle. Then,
\[
\sin x = \frac{50}{41} = 1 + \frac{9}{41}.
\]
Since \( \sin 90^{\circ} = 1 \) and \( \sin 12^{\circ} 40' 49'' = 9/41 \), the angle \( x = 90^{\circ} + 12^{\circ} 40' 49'' = 102^{\circ} 40' 49''\).
Find the triangle with the smallest area with integer sidelengths and possessing this property (that the wrong argument as above gives the correct answer).