2015-12 Rank

Let \(A\) be an \(n\times n\) matrix with complex entries. Prove that if \(A^2=A^*\), then \[\operatorname{rank}(A+A^*)=\operatorname{rank}(A).\] (Here, \(A^*\) is the conjugate transpose of \(A\).)

(This is the last problem of this semester. Thank you for participating KAIST Math Problem of the Week.)

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2015-12 Rank, 3.8 out of 5 based on 6 ratings